(2s+2)+(3s-2)=110

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Solution for (2s+2)+(3s-2)=110 equation: 



(2s+2)+(3s-2)=110

We move all terms to the left:

(2s+2)+(3s-2)-(110)=0

We get rid of parentheses

2s+3s+2-2-110=0

We add all the numbers together, and all the variables

5s-110=0

We move all terms containing s to the left, all other terms to the right

5s=110

s=110/5

s=22

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