(2s+3)+(x+1)=

Solution for (2s+3)+(x+1)= equation:

Simplifying
(2s + 3) + (x + 1) = 0

Reorder the terms:
(3 + 2s) + (x + 1) = 0

Remove parenthesis around (3 + 2s)
3 + 2s + (x + 1) = 0

Reorder the terms:
3 + 2s + (1 + x) = 0

Remove parenthesis around (1 + x)
3 + 2s + 1 + x = 0

Reorder the terms:
3 + 1 + 2s + x = 0

Combine like terms: 3 + 1 = 4
4 + 2s + x = 0

Solving
4 + 2s + x = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 2s + -4 + x = 0 + -4

Reorder the terms:
4 + -4 + 2s + x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2s + x = 0 + -4
2s + x = 0 + -4

Combine like terms: 0 + -4 = -4
2s + x = -4

Add '-1x' to each side of the equation.
2s + x + -1x = -4 + -1x

Combine like terms: x + -1x = 0
2s + 0 = -4 + -1x
2s = -4 + -1x

Divide each side by '2'.
s = -2 + -0.5x

Simplifying
s = -2 + -0.5x