(2s+4)(2s-4)=

Solution for (2s+4)(2s-4)= equation:

Simplifying
(2s + 4)(2s + -4) = 0

Reorder the terms:
(4 + 2s)(2s + -4) = 0

Reorder the terms:
(4 + 2s)(-4 + 2s) = 0

Multiply (4 + 2s) * (-4 + 2s)
(4(-4 + 2s) + 2s * (-4 + 2s)) = 0
((-4 * 4 + 2s * 4) + 2s * (-4 + 2s)) = 0
((-16 + 8s) + 2s * (-4 + 2s)) = 0
(-16 + 8s + (-4 * 2s + 2s * 2s)) = 0
(-16 + 8s + (-8s + 4s2)) = 0

Combine like terms: 8s + -8s = 0
(-16 + 0 + 4s2) = 0
(-16 + 4s2) = 0

Solving
-16 + 4s2 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4s2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4s2 = 0 + 16
4s2 = 0 + 16

Combine like terms: 0 + 16 = 16
4s2 = 16

Divide each side by '4'.
s2 = 4

Simplifying
s2 = 4

Take the square root of each side:
s = {-2, 2}