(2s+5)(2s-5)=0

Solution for (2s+5)(2s-5)=0 equation:

Simplifying
(2s + 5)(2s + -5) = 0

Reorder the terms:
(5 + 2s)(2s + -5) = 0

Reorder the terms:
(5 + 2s)(-5 + 2s) = 0

Multiply (5 + 2s) * (-5 + 2s)
(5(-5 + 2s) + 2s * (-5 + 2s)) = 0
((-5 * 5 + 2s * 5) + 2s * (-5 + 2s)) = 0
((-25 + 10s) + 2s * (-5 + 2s)) = 0
(-25 + 10s + (-5 * 2s + 2s * 2s)) = 0
(-25 + 10s + (-10s + 4s2)) = 0

Combine like terms: 10s + -10s = 0
(-25 + 0 + 4s2) = 0
(-25 + 4s2) = 0

Solving
-25 + 4s2 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4s2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4s2 = 0 + 25
4s2 = 0 + 25

Combine like terms: 0 + 25 = 25
4s2 = 25

Divide each side by '4'.
s2 = 6.25

Simplifying
s2 = 6.25

Take the square root of each side:
s = {-2.5, 2.5}