(2s+7)(8s+9)=0

Solution for (2s+7)(8s+9)=0 equation:

(2s+7)(8s+9)=0

We multiply parentheses ..

(+16s^2+18s+56s+63)=0

We get rid of parentheses

16s^2+18s+56s+63=0

We add all the numbers together, and all the variables

16s^2+74s+63=0

a = 16; b = 74; c = +63;
Δ = b2-4ac
Δ = 742-4·16·63
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-38}{2*16}=\frac{-112}{32}
=-3+1/2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+38}{2*16}=\frac{-36}{32}
=-1+1/8
$