(2s-10)+(2s-11)+(2s-9)=180

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Solution for (2s-10)+(2s-11)+(2s-9)=180 equation: 



(2s-10)+(2s-11)+(2s-9)=180

We move all terms to the left:

(2s-10)+(2s-11)+(2s-9)-(180)=0

We get rid of parentheses

2s+2s+2s-10-11-9-180=0

We add all the numbers together, and all the variables

6s-210=0

We move all terms containing s to the left, all other terms to the right

6s=210

s=210/6

s=35

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