(2s-3)(2s+3)=0

Solution for (2s-3)(2s+3)=0 equation:

Simplifying
(2s + -3)(2s + 3) = 0

Reorder the terms:
(-3 + 2s)(2s + 3) = 0

Reorder the terms:
(-3 + 2s)(3 + 2s) = 0

Multiply (-3 + 2s) * (3 + 2s)
(-3(3 + 2s) + 2s * (3 + 2s)) = 0
((3 * -3 + 2s * -3) + 2s * (3 + 2s)) = 0
((-9 + -6s) + 2s * (3 + 2s)) = 0
(-9 + -6s + (3 * 2s + 2s * 2s)) = 0
(-9 + -6s + (6s + 4s2)) = 0

Combine like terms: -6s + 6s = 0
(-9 + 0 + 4s2) = 0
(-9 + 4s2) = 0

Solving
-9 + 4s2 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 4s2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 4s2 = 0 + 9
4s2 = 0 + 9

Combine like terms: 0 + 9 = 9
4s2 = 9

Divide each side by '4'.
s2 = 2.25

Simplifying
s2 = 2.25

Take the square root of each side:
s = {-1.5, 1.5}