(2s-5)/(s+2)=3/2

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Solution for (2s-5)/(s+2)=3/2 equation: 



(2s-5)/(s+2)=3/2

We move all terms to the left:

(2s-5)/(s+2)-(3/2)=0



Domain of the equation: (s+2)!=0

We move all terms containing s to the left, all other terms to the right

s!=-2

s∈R



We add all the numbers together, and all the variables

(2s-5)/(s+2)-(+3/2)=0

We get rid of parentheses

(2s-5)/(s+2)-3/2=0

We calculate fractions


(4s-10)/(2s+4)+(-3s-6)/(2s+4)=0

We multiply all the terms by the denominator


(4s-10)+(-3s-6)=0

We get rid of parentheses

4s-3s-10-6=0

We add all the numbers together, and all the variables

s-16=0

We move all terms containing s to the left, all other terms to the right

s=16

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