(2senx-1)(2senx+1)=0

Solution for (2senx-1)(2senx+1)=0 equation:

Simplifying
(2senx + -1)(2senx + 1) = 0

Reorder the terms:
(-1 + 2ensx)(2senx + 1) = 0

Reorder the terms:
(-1 + 2ensx)(1 + 2ensx) = 0

Multiply (-1 + 2ensx) * (1 + 2ensx)
(-1(1 + 2ensx) + 2ensx * (1 + 2ensx)) = 0
((1 * -1 + 2ensx * -1) + 2ensx * (1 + 2ensx)) = 0
((-1 + -2ensx) + 2ensx * (1 + 2ensx)) = 0
(-1 + -2ensx + (1 * 2ensx + 2ensx * 2ensx)) = 0
(-1 + -2ensx + (2ensx + 4e2n2s2x2)) = 0

Combine like terms: -2ensx + 2ensx = 0
(-1 + 0 + 4e2n2s2x2) = 0
(-1 + 4e2n2s2x2) = 0

Solving
-1 + 4e2n2s2x2 = 0

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4e2n2s2x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4e2n2s2x2 = 0 + 1
4e2n2s2x2 = 0 + 1

Combine like terms: 0 + 1 = 1
4e2n2s2x2 = 1

Divide each side by '4n2s2x2'.
e2 = 0.25n-2s-2x-2

Simplifying
e2 = 0.25n-2s-2x-2

Take the square root of each side:
e = {-0.5n-1s-1x-1, 0.5n-1s-1x-1}