(2t)+8+((1/2)t)-(1t)=11

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Solution for (2t)+8+((1/2)t)-(1t)=11 equation: 



(2t)+8+((1/2)t)-(1t)=11

We move all terms to the left:

(2t)+8+((1/2)t)-(1t)-(11)=0



Domain of the equation: 2)t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

2t+((+1/2)t)-1t+8-11=0

We add all the numbers together, and all the variables

t+((+1/2)t)-3=0

We multiply all the terms by the denominator


t*2)t)+((-3*2)t)+1=0

We add all the numbers together, and all the variables

t*2)t)+((-6)t)+1=0

Wy multiply elements

2t^2-6)t)+1=0

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