(2t+1)(t+5)=

Solution for (2t+1)(t+5)= equation:

Simplifying
(2t + 1)(t + 5) = 0

Reorder the terms:
(1 + 2t)(t + 5) = 0

Reorder the terms:
(1 + 2t)(5 + t) = 0

Multiply (1 + 2t) * (5 + t)
(1(5 + t) + 2t * (5 + t)) = 0
((5 * 1 + t * 1) + 2t * (5 + t)) = 0
((5 + 1t) + 2t * (5 + t)) = 0
(5 + 1t + (5 * 2t + t * 2t)) = 0
(5 + 1t + (10t + 2t2)) = 0

Combine like terms: 1t + 10t = 11t
(5 + 11t + 2t2) = 0

Solving
5 + 11t + 2t2 = 0

Solving for variable 't'.

Factor a trinomial.
(5 + t)(1 + 2t) = 0

Subproblem 1
Set the factor '(5 + t)' equal to zero and attempt to solve:

Simplifying
5 + t = 0

Solving
5 + t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + t = 0 + -5

Combine like terms: 5 + -5 = 0
0 + t = 0 + -5
t = 0 + -5

Combine like terms: 0 + -5 = -5
t = -5

Simplifying
t = -5
Subproblem 2
Set the factor '(1 + 2t)' equal to zero and attempt to solve:

Simplifying
1 + 2t = 0

Solving
1 + 2t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2t = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2t = 0 + -1
2t = 0 + -1

Combine like terms: 0 + -1 = -1
2t = -1

Divide each side by '2'.
t = -0.5

Simplifying
t = -0.5
Solution
t = {-5, -0.5}