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(2t+3)=(2t-4)
We move all terms to the left:
(2t+3)-((2t-4))=0
We get rid of parentheses
2t-((2t-4))+3=0
We calculate terms in parentheses: -((2t-4)), so:We get rid of parentheses
(2t-4)
We get rid of parentheses
2t-4
Back to the equation:
-(2t-4)
2t-2t+4+3=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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