(2t+5x)(2t-5x)=0

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Solution for (2t+5x)(2t-5x)=0 equation:


Simplifying
(2t + 5x)(2t + -5x) = 0

Multiply (2t + 5x) * (2t + -5x)
(2t * (2t + -5x) + 5x * (2t + -5x)) = 0
((2t * 2t + -5x * 2t) + 5x * (2t + -5x)) = 0

Reorder the terms:
((-10tx + 4t2) + 5x * (2t + -5x)) = 0
((-10tx + 4t2) + 5x * (2t + -5x)) = 0
(-10tx + 4t2 + (2t * 5x + -5x * 5x)) = 0
(-10tx + 4t2 + (10tx + -25x2)) = 0

Reorder the terms:
(-10tx + 10tx + 4t2 + -25x2) = 0

Combine like terms: -10tx + 10tx = 0
(0 + 4t2 + -25x2) = 0
(4t2 + -25x2) = 0

Solving
4t2 + -25x2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '25x2' to each side of the equation.
4t2 + -25x2 + 25x2 = 0 + 25x2

Combine like terms: -25x2 + 25x2 = 0
4t2 + 0 = 0 + 25x2
4t2 = 0 + 25x2
Remove the zero:
4t2 = 25x2

Divide each side by '4'.
t2 = 6.25x2

Simplifying
t2 = 6.25x2

Take the square root of each side:
t = {-2.5x, 2.5x}

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