(2t-1)(2t+1)=

Solution for (2t-1)(2t+1)= equation:

Simplifying
(2t + -1)(2t + 1) = 0

Reorder the terms:
(-1 + 2t)(2t + 1) = 0

Reorder the terms:
(-1 + 2t)(1 + 2t) = 0

Multiply (-1 + 2t) * (1 + 2t)
(-1(1 + 2t) + 2t * (1 + 2t)) = 0
((1 * -1 + 2t * -1) + 2t * (1 + 2t)) = 0
((-1 + -2t) + 2t * (1 + 2t)) = 0
(-1 + -2t + (1 * 2t + 2t * 2t)) = 0
(-1 + -2t + (2t + 4t2)) = 0

Combine like terms: -2t + 2t = 0
(-1 + 0 + 4t2) = 0
(-1 + 4t2) = 0

Solving
-1 + 4t2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4t2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4t2 = 0 + 1
4t2 = 0 + 1

Combine like terms: 0 + 1 = 1
4t2 = 1

Divide each side by '4'.
t2 = 0.25

Simplifying
t2 = 0.25

Take the square root of each side:
t = {-0.5, 0.5}