(2t-1)/3=(3t+2)/15

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Solution for (2t-1)/3=(3t+2)/15 equation: 



(2t-1)/3=(3t+2)/15

We move all terms to the left:

(2t-1)/3-((3t+2)/15)=0

We calculate fractions


2t/()+(-((3t+2)*3)/()=0



We calculate terms in parentheses: +(-((3t+2)*3)/(), so:

-((3t+2)*3)/(

We multiply all the terms by the denominator


-((3t+2)*3)



We calculate terms in parentheses: -((3t+2)*3), so:

(3t+2)*3

We multiply parentheses

9t+6

Back to the equation:

-(9t+6)



We get rid of parentheses

-9t-6

Back to the equation:

+(-9t-6)



We get rid of parentheses

2t/()-9t-6=0

We multiply all the terms by the denominator


2t-9t*()-6*()=0

We add all the numbers together, and all the variables

2t-9t*()=0

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