(2t-1)/6=(9-2t)/10

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Solution for (2t-1)/6=(9-2t)/10 equation: 



(2t-1)/6=(9-2t)/10

We move all terms to the left:

(2t-1)/6-((9-2t)/10)=0

We add all the numbers together, and all the variables

(2t-1)/6-((-2t+9)/10)=0

We calculate fractions


2t/()+(-((-2t+9)*6)/()=0



We calculate terms in parentheses: +(-((-2t+9)*6)/(), so:

-((-2t+9)*6)/(

We multiply all the terms by the denominator


-((-2t+9)*6)



We calculate terms in parentheses: -((-2t+9)*6), so:

(-2t+9)*6

We multiply parentheses

-12t+54

Back to the equation:

-(-12t+54)



We get rid of parentheses

12t-54

Back to the equation:

+(12t-54)



We get rid of parentheses

2t/()+12t-54=0

We multiply all the terms by the denominator


2t+12t*()-54*()=0

We add all the numbers together, and all the variables

2t+12t*()=0

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