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(2t-3)(4t+4)=(2t+7)(4t-3)
We move all terms to the left:
(2t-3)(4t+4)-((2t+7)(4t-3))=0
We multiply parentheses ..
(+8t^2+8t-12t-12)-((2t+7)(4t-3))=0
We calculate terms in parentheses: -((2t+7)(4t-3)), so:We get rid of parentheses
(2t+7)(4t-3)
We multiply parentheses ..
(+8t^2-6t+28t-21)
We get rid of parentheses
8t^2-6t+28t-21
We add all the numbers together, and all the variables
8t^2+22t-21
Back to the equation:
-(8t^2+22t-21)
8t^2-8t^2+8t-12t-22t-12+21=0
We add all the numbers together, and all the variables
-26t+9=0
We move all terms containing t to the left, all other terms to the right
-26t=-9
t=-9/-26
t=9/26
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