(2t-33)+(t-36)+(t-36)+(t-20)+122=360

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Solution for (2t-33)+(t-36)+(t-36)+(t-20)+122=360 equation: 



(2t-33)+(t-36)+(t-36)+(t-20)+122=360

We move all terms to the left:

(2t-33)+(t-36)+(t-36)+(t-20)+122-(360)=0

We add all the numbers together, and all the variables

(2t-33)+(t-36)+(t-36)+(t-20)-238=0

We get rid of parentheses

2t+t+t+t-33-36-36-20-238=0

We add all the numbers together, and all the variables

5t-363=0

We move all terms containing t to the left, all other terms to the right

5t=363

t=363/5

t=72+3/5

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