(2t-4)-8(2t-4)+12=0

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Solution for (2t-4)-8(2t-4)+12=0 equation:


Simplifying
(2t + -4) + -8(2t + -4) + 12 = 0

Reorder the terms:
(-4 + 2t) + -8(2t + -4) + 12 = 0

Remove parenthesis around (-4 + 2t)
-4 + 2t + -8(2t + -4) + 12 = 0

Reorder the terms:
-4 + 2t + -8(-4 + 2t) + 12 = 0
-4 + 2t + (-4 * -8 + 2t * -8) + 12 = 0
-4 + 2t + (32 + -16t) + 12 = 0

Reorder the terms:
-4 + 32 + 12 + 2t + -16t = 0

Combine like terms: -4 + 32 = 28
28 + 12 + 2t + -16t = 0

Combine like terms: 28 + 12 = 40
40 + 2t + -16t = 0

Combine like terms: 2t + -16t = -14t
40 + -14t = 0

Solving
40 + -14t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + -14t = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -14t = 0 + -40
-14t = 0 + -40

Combine like terms: 0 + -40 = -40
-14t = -40

Divide each side by '-14'.
t = 2.857142857

Simplifying
t = 2.857142857

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