(2t-40)/(3t+19)=-1

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Solution for (2t-40)/(3t+19)=-1 equation:



(2t-40)/(3t+19)=-1
We move all terms to the left:
(2t-40)/(3t+19)-(-1)=0
Domain of the equation: (3t+19)!=0
We move all terms containing t to the left, all other terms to the right
3t!=-19
t!=-19/3
t!=-6+1/3
t∈R
We add all the numbers together, and all the variables
(2t-40)/(3t+19)+1=0
We multiply all the terms by the denominator
(2t-40)+1*(3t+19)=0
We get rid of parentheses
2t+1*(3t+19)-40=0
We move all terms containing t to the left, all other terms to the right
2t+1*(3t+19)=40

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