(2t-40)/(3t+19)=-1

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Solution for (2t-40)/(3t+19)=-1 equation: 



(2t-40)/(3t+19)=-1

We move all terms to the left:

(2t-40)/(3t+19)-(-1)=0



Domain of the equation: (3t+19)!=0

We move all terms containing t to the left, all other terms to the right

3t!=-19

t!=-19/3

t!=-6+1/3

t∈R



We add all the numbers together, and all the variables

(2t-40)/(3t+19)+1=0

We multiply all the terms by the denominator


(2t-40)+1*(3t+19)=0

We get rid of parentheses

2t+1*(3t+19)-40=0

We move all terms containing t to the left, all other terms to the right

2t+1*(3t+19)=40

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