(2t-5)(2t+5)=0

Solution for (2t-5)(2t+5)=0 equation:

Simplifying
(2t + -5)(2t + 5) = 0

Reorder the terms:
(-5 + 2t)(2t + 5) = 0

Reorder the terms:
(-5 + 2t)(5 + 2t) = 0

Multiply (-5 + 2t) * (5 + 2t)
(-5(5 + 2t) + 2t * (5 + 2t)) = 0
((5 * -5 + 2t * -5) + 2t * (5 + 2t)) = 0
((-25 + -10t) + 2t * (5 + 2t)) = 0
(-25 + -10t + (5 * 2t + 2t * 2t)) = 0
(-25 + -10t + (10t + 4t2)) = 0

Combine like terms: -10t + 10t = 0
(-25 + 0 + 4t2) = 0
(-25 + 4t2) = 0

Solving
-25 + 4t2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4t2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4t2 = 0 + 25
4t2 = 0 + 25

Combine like terms: 0 + 25 = 25
4t2 = 25

Divide each side by '4'.
t2 = 6.25

Simplifying
t2 = 6.25

Take the square root of each side:
t = {-2.5, 2.5}