(2t-7)/3=33

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Solution for (2t-7)/3=33 equation: 



(2t-7)/3=33

We move all terms to the left:

(2t-7)/3-(33)=0

We multiply all the terms by the denominator


(2t-7)-33*3=0

We add all the numbers together, and all the variables

(2t-7)-99=0

We get rid of parentheses

2t-7-99=0

We add all the numbers together, and all the variables

2t-106=0

We move all terms containing t to the left, all other terms to the right

2t=106

t=106/2

t=53

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