(2t-84)+(2t-54)=(2t-84)+(2t-54)

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Solution for (2t-84)+(2t-54)=(2t-84)+(2t-54) equation: 



(2t-84)+(2t-54)=(2t-84)+(2t-54)

We move all terms to the left:

(2t-84)+(2t-54)-((2t-84)+(2t-54))=0

We get rid of parentheses

2t+2t-((2t-84)+(2t-54))-84-54=0



We calculate terms in parentheses: -((2t-84)+(2t-54)), so:

(2t-84)+(2t-54)

We get rid of parentheses

2t+2t-84-54

We add all the numbers together, and all the variables

4t-138

Back to the equation:

-(4t-138)



We add all the numbers together, and all the variables

4t-(4t-138)-138=0

We get rid of parentheses

4t-4t+138-138=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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