(2t2+13t+12)/(3t+4)

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Solution for (2t2+13t+12)/(3t+4) equation:


D( t )

3*t+4 = 0

3*t+4 = 0

3*t+4 = 0

3*t+4 = 0 // - 4

3*t = -4 // : 3

t = -4/3

t in (-oo:-4/3) U (-4/3:+oo)

(2*t^2+13*t+12)/(3*t+4) = 0

2*t^2+13*t+12 = 0

2*t^2+13*t+12 = 0

DELTA = 13^2-(2*4*12)

DELTA = 73

DELTA > 0

t = (73^(1/2)-13)/(2*2) or t = (-73^(1/2)-13)/(2*2)

t = (73^(1/2)-13)/4 or t = (-(73^(1/2)+13))/4

(t+(73^(1/2)+13)/4)*(t-((73^(1/2)-13)/4)) = 0

((t+(73^(1/2)+13)/4)*(t-((73^(1/2)-13)/4)))/(3*t+4) = 0

( t+(73^(1/2)+13)/4 )

t+(73^(1/2)+13)/4 = 0 // - (73^(1/2)+13)/4

t = -((73^(1/2)+13)/4)

( t-((73^(1/2)-13)/4) )

t-((73^(1/2)-13)/4) = 0 // + (73^(1/2)-13)/4

t = (73^(1/2)-13)/4

t in { -((73^(1/2)+13)/4), (73^(1/2)-13)/4 }

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