(2t2-5t-1)=(3t2-6t+4)

Solution for (2t2-5t-1)=(3t2-6t+4) equation:

(2t^2-5t-1)=(3t^2-6t+4)

We move all terms to the left:

(2t^2-5t-1)-((3t^2-6t+4))=0

We get rid of parentheses

2t^2-5t-((3t^2-6t+4))-1=0


We calculate terms in parentheses: -((3t^2-6t+4)), so:

(3t^2-6t+4)

We get rid of parentheses

3t^2-6t+4

Back to the equation:

-(3t^2-6t+4)


We get rid of parentheses

2t^2-3t^2-5t+6t-4-1=0

We add all the numbers together, and all the variables

-1t^2+t-5=0

a = -1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation