(2u+1)(2u-1)=

Solution for (2u+1)(2u-1)= equation:

Simplifying
(2u + 1)(2u + -1) = 0

Reorder the terms:
(1 + 2u)(2u + -1) = 0

Reorder the terms:
(1 + 2u)(-1 + 2u) = 0

Multiply (1 + 2u) * (-1 + 2u)
(1(-1 + 2u) + 2u * (-1 + 2u)) = 0
((-1 * 1 + 2u * 1) + 2u * (-1 + 2u)) = 0
((-1 + 2u) + 2u * (-1 + 2u)) = 0
(-1 + 2u + (-1 * 2u + 2u * 2u)) = 0
(-1 + 2u + (-2u + 4u2)) = 0

Combine like terms: 2u + -2u = 0
(-1 + 0 + 4u2) = 0
(-1 + 4u2) = 0

Solving
-1 + 4u2 = 0

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4u2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4u2 = 0 + 1
4u2 = 0 + 1

Combine like terms: 0 + 1 = 1
4u2 = 1

Divide each side by '4'.
u2 = 0.25

Simplifying
u2 = 0.25

Take the square root of each side:
u = {-0.5, 0.5}