(2u+1)(8+u)=0

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Solution for (2u+1)(8+u)=0 equation:


Simplifying
(2u + 1)(8 + u) = 0

Reorder the terms:
(1 + 2u)(8 + u) = 0

Multiply (1 + 2u) * (8 + u)
(1(8 + u) + 2u * (8 + u)) = 0
((8 * 1 + u * 1) + 2u * (8 + u)) = 0
((8 + 1u) + 2u * (8 + u)) = 0
(8 + 1u + (8 * 2u + u * 2u)) = 0
(8 + 1u + (16u + 2u2)) = 0

Combine like terms: 1u + 16u = 17u
(8 + 17u + 2u2) = 0

Solving
8 + 17u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(8 + u)(1 + 2u) = 0

Subproblem 1

Set the factor '(8 + u)' equal to zero and attempt to solve: Simplifying 8 + u = 0 Solving 8 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + u = 0 + -8 Combine like terms: 8 + -8 = 0 0 + u = 0 + -8 u = 0 + -8 Combine like terms: 0 + -8 = -8 u = -8 Simplifying u = -8

Subproblem 2

Set the factor '(1 + 2u)' equal to zero and attempt to solve: Simplifying 1 + 2u = 0 Solving 1 + 2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2u = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2u = 0 + -1 2u = 0 + -1 Combine like terms: 0 + -1 = -1 2u = -1 Divide each side by '2'. u = -0.5 Simplifying u = -0.5

Solution

u = {-8, -0.5}

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