(2u+1)+(3u+5)=11

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Solution for (2u+1)+(3u+5)=11 equation:


Simplifying
(2u + 1) + (3u + 5) = 11

Reorder the terms:
(1 + 2u) + (3u + 5) = 11

Remove parenthesis around (1 + 2u)
1 + 2u + (3u + 5) = 11

Reorder the terms:
1 + 2u + (5 + 3u) = 11

Remove parenthesis around (5 + 3u)
1 + 2u + 5 + 3u = 11

Reorder the terms:
1 + 5 + 2u + 3u = 11

Combine like terms: 1 + 5 = 6
6 + 2u + 3u = 11

Combine like terms: 2u + 3u = 5u
6 + 5u = 11

Solving
6 + 5u = 11

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 5u = 11 + -6

Combine like terms: 6 + -6 = 0
0 + 5u = 11 + -6
5u = 11 + -6

Combine like terms: 11 + -6 = 5
5u = 5

Divide each side by '5'.
u = 1

Simplifying
u = 1

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