(2u+1)2/3=(3)

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Solution for (2u+1)2/3=(3) equation: 


u in (-oo:+oo)

((2*u+1)^2)/3 = 3 // - 3

((2*u+1)^2)/3-3 = 0

((2*u+1)^2)/3+(-3*3)/3 = 0

(2*u+1)^2-3*3 = 0

4*u^2+4*u-8 = 0

4*u^2+4*u-8 = 0

4*(u^2+u-2) = 0

u^2+u-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

u = (9^(1/2)-1)/(1*2) or u = (-9^(1/2)-1)/(1*2)

u = 1 or u = -2

4*(u+2)*(u-1) = 0

(4*(u+2)*(u-1))/3 = 0

(4*(u+2)*(u-1))/3 = 0 // * 3

4*(u+2)*(u-1) = 0

( u+2 )

u+2 = 0 // - 2

u = -2

( u-1 )

u-1 = 0 // + 1

u = 1

u in { -2, 1 }

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