(2u+3)(2+u)=0

Solution for (2u+3)(2+u)=0 equation:

Simplifying
(2u + 3)(2 + u) = 0

Reorder the terms:
(3 + 2u)(2 + u) = 0

Multiply (3 + 2u) * (2 + u)
(3(2 + u) + 2u * (2 + u)) = 0
((2 * 3 + u * 3) + 2u * (2 + u)) = 0
((6 + 3u) + 2u * (2 + u)) = 0
(6 + 3u + (2 * 2u + u * 2u)) = 0
(6 + 3u + (4u + 2u2)) = 0

Combine like terms: 3u + 4u = 7u
(6 + 7u + 2u2) = 0

Solving
6 + 7u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(2 + u)(3 + 2u) = 0

Subproblem 1
Set the factor '(2 + u)' equal to zero and attempt to solve:

Simplifying
2 + u = 0

Solving
2 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + u = 0 + -2
u = 0 + -2

Combine like terms: 0 + -2 = -2
u = -2

Simplifying
u = -2
Subproblem 2
Set the factor '(3 + 2u)' equal to zero and attempt to solve:

Simplifying
3 + 2u = 0

Solving
3 + 2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2u = 0 + -3
2u = 0 + -3

Combine like terms: 0 + -3 = -3
2u = -3

Divide each side by '2'.
u = -1.5

Simplifying
u = -1.5
Solution
u = {-2, -1.5}