(2u+3)(5+u)=0

Solution for (2u+3)(5+u)=0 equation:

Simplifying
(2u + 3)(5 + u) = 0

Reorder the terms:
(3 + 2u)(5 + u) = 0

Multiply (3 + 2u) * (5 + u)
(3(5 + u) + 2u * (5 + u)) = 0
((5 * 3 + u * 3) + 2u * (5 + u)) = 0
((15 + 3u) + 2u * (5 + u)) = 0
(15 + 3u + (5 * 2u + u * 2u)) = 0
(15 + 3u + (10u + 2u2)) = 0

Combine like terms: 3u + 10u = 13u
(15 + 13u + 2u2) = 0

Solving
15 + 13u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(5 + u)(3 + 2u) = 0

Subproblem 1
Set the factor '(5 + u)' equal to zero and attempt to solve:

Simplifying
5 + u = 0

Solving
5 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + u = 0 + -5

Combine like terms: 5 + -5 = 0
0 + u = 0 + -5
u = 0 + -5

Combine like terms: 0 + -5 = -5
u = -5

Simplifying
u = -5
Subproblem 2
Set the factor '(3 + 2u)' equal to zero and attempt to solve:

Simplifying
3 + 2u = 0

Solving
3 + 2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2u = 0 + -3
2u = 0 + -3

Combine like terms: 0 + -3 = -3
2u = -3

Divide each side by '2'.
u = -1.5

Simplifying
u = -1.5
Solution
u = {-5, -1.5}