(2u+4)(u+1)=0

Solution for (2u+4)(u+1)=0 equation:

Simplifying
(2u + 4)(u + 1) = 0

Reorder the terms:
(4 + 2u)(u + 1) = 0

Reorder the terms:
(4 + 2u)(1 + u) = 0

Multiply (4 + 2u) * (1 + u)
(4(1 + u) + 2u * (1 + u)) = 0
((1 * 4 + u * 4) + 2u * (1 + u)) = 0
((4 + 4u) + 2u * (1 + u)) = 0
(4 + 4u + (1 * 2u + u * 2u)) = 0
(4 + 4u + (2u + 2u2)) = 0

Combine like terms: 4u + 2u = 6u
(4 + 6u + 2u2) = 0

Solving
4 + 6u + 2u2 = 0

Solving for variable 'u'.

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + 3u + u2) = 0

Factor a trinomial.
2((2 + u)(1 + u)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(2 + u)' equal to zero and attempt to solve:

Simplifying
2 + u = 0

Solving
2 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + u = 0 + -2
u = 0 + -2

Combine like terms: 0 + -2 = -2
u = -2

Simplifying
u = -2
Subproblem 2
Set the factor '(1 + u)' equal to zero and attempt to solve:

Simplifying
1 + u = 0

Solving
1 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + u = 0 + -1

Combine like terms: 1 + -1 = 0
0 + u = 0 + -1
u = 0 + -1

Combine like terms: 0 + -1 = -1
u = -1

Simplifying
u = -1
Solution
u = {-2, -1}