(2u+5v)(2u-5v)=

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Solution for (2u+5v)(2u-5v)= equation:


Simplifying
(2u + 5v)(2u + -5v) = 0

Multiply (2u + 5v) * (2u + -5v)
(2u * (2u + -5v) + 5v * (2u + -5v)) = 0
((2u * 2u + -5v * 2u) + 5v * (2u + -5v)) = 0

Reorder the terms:
((-10uv + 4u2) + 5v * (2u + -5v)) = 0
((-10uv + 4u2) + 5v * (2u + -5v)) = 0
(-10uv + 4u2 + (2u * 5v + -5v * 5v)) = 0
(-10uv + 4u2 + (10uv + -25v2)) = 0

Reorder the terms:
(-10uv + 10uv + 4u2 + -25v2) = 0

Combine like terms: -10uv + 10uv = 0
(0 + 4u2 + -25v2) = 0
(4u2 + -25v2) = 0

Solving
4u2 + -25v2 = 0

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '25v2' to each side of the equation.
4u2 + -25v2 + 25v2 = 0 + 25v2

Combine like terms: -25v2 + 25v2 = 0
4u2 + 0 = 0 + 25v2
4u2 = 0 + 25v2
Remove the zero:
4u2 = 25v2

Divide each side by '4'.
u2 = 6.25v2

Simplifying
u2 = 6.25v2

Take the square root of each side:
u = {-2.5v, 2.5v}

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