(2u-3)(2+u)=0

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Solution for (2u-3)(2+u)=0 equation:


Simplifying
(2u + -3)(2 + u) = 0

Reorder the terms:
(-3 + 2u)(2 + u) = 0

Multiply (-3 + 2u) * (2 + u)
(-3(2 + u) + 2u * (2 + u)) = 0
((2 * -3 + u * -3) + 2u * (2 + u)) = 0
((-6 + -3u) + 2u * (2 + u)) = 0
(-6 + -3u + (2 * 2u + u * 2u)) = 0
(-6 + -3u + (4u + 2u2)) = 0

Combine like terms: -3u + 4u = 1u
(-6 + 1u + 2u2) = 0

Solving
-6 + 1u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-2 + -1u)(3 + -2u) = 0

Subproblem 1

Set the factor '(-2 + -1u)' equal to zero and attempt to solve: Simplifying -2 + -1u = 0 Solving -2 + -1u = 0 Move all terms containing u to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1u = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1u = 0 + 2 -1u = 0 + 2 Combine like terms: 0 + 2 = 2 -1u = 2 Divide each side by '-1'. u = -2 Simplifying u = -2

Subproblem 2

Set the factor '(3 + -2u)' equal to zero and attempt to solve: Simplifying 3 + -2u = 0 Solving 3 + -2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2u = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2u = 0 + -3 -2u = 0 + -3 Combine like terms: 0 + -3 = -3 -2u = -3 Divide each side by '-2'. u = 1.5 Simplifying u = 1.5

Solution

u = {-2, 1.5}

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