(2u-5)(2+u)=0

Solution for (2u-5)(2+u)=0 equation:

Simplifying
(2u + -5)(2 + u) = 0

Reorder the terms:
(-5 + 2u)(2 + u) = 0

Multiply (-5 + 2u) * (2 + u)
(-5(2 + u) + 2u * (2 + u)) = 0
((2 * -5 + u * -5) + 2u * (2 + u)) = 0
((-10 + -5u) + 2u * (2 + u)) = 0
(-10 + -5u + (2 * 2u + u * 2u)) = 0
(-10 + -5u + (4u + 2u2)) = 0

Combine like terms: -5u + 4u = -1u
(-10 + -1u + 2u2) = 0

Solving
-10 + -1u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-2 + -1u)(5 + -2u) = 0

Subproblem 1
Set the factor '(-2 + -1u)' equal to zero and attempt to solve:

Simplifying
-2 + -1u = 0

Solving
-2 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1u = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1u = 0 + 2
-1u = 0 + 2

Combine like terms: 0 + 2 = 2
-1u = 2

Divide each side by '-1'.
u = -2

Simplifying
u = -2
Subproblem 2
Set the factor '(5 + -2u)' equal to zero and attempt to solve:

Simplifying
5 + -2u = 0

Solving
5 + -2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -2u = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2u = 0 + -5
-2u = 0 + -5

Combine like terms: 0 + -5 = -5
-2u = -5

Divide each side by '-2'.
u = 2.5

Simplifying
u = 2.5
Solution
u = {-2, 2.5}