(2u-9)(2u=9)

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Solution for (2u-9)(2u=9) equation: 



(2u-9)(2u=9)

We move all terms to the left:

(2u-9)(2u-(9))=0

We multiply parentheses ..

(+4u^2-18u-18u+81)=0

We get rid of parentheses

4u^2-18u-18u+81=0

We add all the numbers together, and all the variables

4u^2-36u+81=0

a = 4; b = -36; c = +81;
Δ = b2-4ac
Δ = -362-4·4·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{36}{8}=4+1/2$

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