If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(((2*u)/3)*v^4)^3 = 0
8/27*u^3*v^12 = 0
x naleu017Cy do R
x in (-oo:+oo)
| 1/3x^2-2x-4=0 | | (2u/3v) | | 25v^3+110v^2-75=0 | | 4v^2+20v+11=0 | | 5+2w=9 | | 3m^2+5m=6 | | 1/3x12x | | 4m^2-2m=8 | | y+21*2=180 | | 95=152/t | | 2x-8=x^2+7x-2 | | 0=-16t^2+95t+6 | | -1.3z-2.6=0 | | y=4(-7)+26 | | 6y=5y^2+1 | | [23-5t]=33 | | 1x^2+3x-4=0 | | 9x-64=8 | | -2x+2(4x+26)=10 | | (x-2)/41-2 | | v(v-5)=14 | | -2+2(4x+26)=10 | | v*2=7v | | x-2/41-2 | | 3x^2-10+7=0 | | 56+11=80+8x | | 2r^2-26r+72=0 | | x+8/x=-9 | | 8x+4y-12=0 | | 21x+31+9x+41=702 | | 6z=2/5 | | 21x+31+9x+41=701 |