(2v+7)(5+v)=0

Solution for (2v+7)(5+v)=0 equation:

(2v+7)(5+v)=0

We add all the numbers together, and all the variables

(2v+7)(v+5)=0

We multiply parentheses ..

(+2v^2+10v+7v+35)=0

We get rid of parentheses

2v^2+10v+7v+35=0

We add all the numbers together, and all the variables

2v^2+17v+35=0

a = 2; b = 17; c = +35;
Δ = b2-4ac
Δ = 172-4·2·35
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3}{2*2}=\frac{-20}{4}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3}{2*2}=\frac{-14}{4}
=-3+1/2
$