(2v-5)(1-v)=0

Solution for (2v-5)(1-v)=0 equation:

(2v-5)(1-v)=0

We add all the numbers together, and all the variables

(2v-5)(-1v+1)=0

We multiply parentheses ..

(-2v^2+2v+5v-5)=0

We get rid of parentheses

-2v^2+2v+5v-5=0

We add all the numbers together, and all the variables

-2v^2+7v-5=0

a = -2; b = 7; c = -5;
Δ = b2-4ac
Δ = 72-4·(-2)·(-5)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*-2}=\frac{-10}{-4}
=2+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*-2}=\frac{-4}{-4}
=1
$