(2w+1)(2w-10)=0

Solution for (2w+1)(2w-10)=0 equation:

(2w+1)(2w-10)=0

We multiply parentheses ..

(+4w^2-20w+2w-10)=0

We get rid of parentheses

4w^2-20w+2w-10=0

We add all the numbers together, and all the variables

4w^2-18w-10=0

a = 4; b = -18; c = -10;
Δ = b2-4ac
Δ = -182-4·4·(-10)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-22}{2*4}=\frac{-4}{8}
=-1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+22}{2*4}=\frac{40}{8}
=5
$