(2w+10)w=168

Solution for (2w+10)w=168 equation:

(2w+10)w=168

We move all terms to the left:

(2w+10)w-(168)=0

We multiply parentheses

2w^2+10w-168=0

a = 2; b = 10; c = -168;
Δ = b2-4ac
Δ = 102-4·2·(-168)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-38}{2*2}=\frac{-48}{4}
=-12
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+38}{2*2}=\frac{28}{4}
=7
$