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(2w+2)(w)=60
We move all terms to the left:
(2w+2)(w)-(60)=0
We multiply parentheses
2w^2+2w-60=0
a = 2; b = 2; c = -60;
Δ = b2-4ac
Δ = 22-4·2·(-60)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*2}=\frac{-24}{4} =-6 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*2}=\frac{20}{4} =5 $
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