(2w+3)(2w+3)=0

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Solution for (2w+3)(2w+3)=0 equation: 



(2w+3)(2w+3)=0

We multiply parentheses ..

(+4w^2+6w+6w+9)=0

We get rid of parentheses

4w^2+6w+6w+9=0

We add all the numbers together, and all the variables

4w^2+12w+9=0

a = 4; b = 12; c = +9;
Δ = b2-4ac
Δ = 122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-12}{8}=-1+1/2$

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