(2w+3)(w)-90=0

Solution for (2w+3)(w)-90=0 equation:

(2w+3)(w)-90=0

We multiply parentheses

2w^2+3w-90=0

a = 2; b = 3; c = -90;
Δ = b2-4ac
Δ = 32-4·2·(-90)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*2}=\frac{-30}{4}
=-7+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*2}=\frac{24}{4}
=6
$