(2w+3)w=78

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Solution for (2w+3)w=78 equation:



(2w+3)w=78
We move all terms to the left:
(2w+3)w-(78)=0
We multiply parentheses
2w^2+3w-78=0
a = 2; b = 3; c = -78;
Δ = b2-4ac
Δ = 32-4·2·(-78)
Δ = 633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{633}}{2*2}=\frac{-3-\sqrt{633}}{4} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{633}}{2*2}=\frac{-3+\sqrt{633}}{4} $

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