(2w+5)(2w+7)+28=0

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Solution for (2w+5)(2w+7)+28=0 equation: 



(2w+5)(2w+7)+28=0

We multiply parentheses ..

(+4w^2+14w+10w+35)+28=0

We get rid of parentheses

4w^2+14w+10w+35+28=0

We add all the numbers together, and all the variables

4w^2+24w+63=0

a = 4; b = 24; c = +63;
Δ = b2-4ac
Δ = 242-4·4·63
Δ = -432
Delta is less than zero, so there is no solution for the equation

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