(2w+5)(3w-4)=0

Solution for (2w+5)(3w-4)=0 equation:

(2w+5)(3w-4)=0

We multiply parentheses ..

(+6w^2-8w+15w-20)=0

We get rid of parentheses

6w^2-8w+15w-20=0

We add all the numbers together, and all the variables

6w^2+7w-20=0

a = 6; b = 7; c = -20;
Δ = b2-4ac
Δ = 72-4·6·(-20)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*6}=\frac{-30}{12}
=-2+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*6}=\frac{16}{12}
=1+1/3
$