(2w+5)(6-w)=0

Solution for (2w+5)(6-w)=0 equation:

(2w+5)(6-w)=0

We add all the numbers together, and all the variables

(2w+5)(-1w+6)=0

We multiply parentheses ..

(-2w^2+12w-5w+30)=0

We get rid of parentheses

-2w^2+12w-5w+30=0

We add all the numbers together, and all the variables

-2w^2+7w+30=0

a = -2; b = 7; c = +30;
Δ = b2-4ac
Δ = 72-4·(-2)·30
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*-2}=\frac{-24}{-4}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*-2}=\frac{10}{-4}
=-2+1/2
$