(2w+9)(8+w)=0

Solution for (2w+9)(8+w)=0 equation:

(2w+9)(8+w)=0

We add all the numbers together, and all the variables

(2w+9)(w+8)=0

We multiply parentheses ..

(+2w^2+16w+9w+72)=0

We get rid of parentheses

2w^2+16w+9w+72=0

We add all the numbers together, and all the variables

2w^2+25w+72=0

a = 2; b = 25; c = +72;
Δ = b2-4ac
Δ = 252-4·2·72
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7}{2*2}=\frac{-32}{4}
=-8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7}{2*2}=\frac{-18}{4}
=-4+1/2
$