(2w+9)w=95

Solution for (2w+9)w=95 equation:

(2w+9)w=95

We move all terms to the left:

(2w+9)w-(95)=0

We multiply parentheses

2w^2+9w-95=0

a = 2; b = 9; c = -95;
Δ = b2-4ac
Δ = 92-4·2·(-95)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-29}{2*2}=\frac{-38}{4}
=-9+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+29}{2*2}=\frac{20}{4}
=5
$